2018/2019 WAEC Further Mathematics Obj And Theory EXPO | 2018 WAEC Further Mathematics QUESTIONS AND ANSWERS EXPO / RUNS - EXAMPASS


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2018/2019 WAEC Further Mathematics Obj And Theory EXPO | 2018 WAEC Further Mathematics QUESTIONS AND ANSWERS EXPO / RUNS

2018 WAEC Further Mathematics QUESTIONS WAEC 2018 Further Mathematics 2018/2019 Waec Further Mathematics Verified/Real Questions And Answers, Expo/Runz | 2018 Waec Further Mathematics Practical Expo.


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FURTHER MATHS

*2018 WAEC MAY/JUNE FURTHER MATHS OBJ AND THEORY*

_Please Note the below symbols_

^ means raise to power
* means multiplication
/ means division

(1)

| x-3 -4 3 |
| 5 2 2 | = -24
| 2 -4 6-x |

(x-3)[2(6-x) +8]+4[5(6-x) -4]+3(-20-4) =-24
(x-3)[-2x+20]+4[-5x+26]+3(-24)= -24
-2x^2+26x-60-20x+104-72= -24
-2x^2+6x-4=0
X^2-3x+2=0
X^2-2x-x+2=0
X(x-2)-1(x-2)=0
(x-1)(x-2)=0
X-1=0 OR x-2=0
X=1 OR x=2

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(2)
Log 3x – 3logx³+ 2 = 0
Log 3x – 3log3³/log3x + 2 = 0
Log3x – 3/log3x + 2 = 0
P – 3/p + 2 = 0 where P = log3x
P² – 3 + 2p = 0
P² + 2p – 3 = 0
(p + 3) ( p – 1) = 0
P = -3 OR p = 1
But log3x = p
when p = -3
Log3x = -3
X = 3-³ = 1/27
And when P = 1
Log3x = 1
X = 3¹ = 3
And X = 1/27 OR 3

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(3a)

U= x-2 ; hence X = u+2
Therefore :
X^3+5/(x-2)^4 = (u+2)^3+5/ (u+2-2)^4
=(u+2)^3+5/u^4

(3b)

(u+2)^3+5/u^4 = (u+2)^3/u^4 + 5/u^4

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No 4
Sn = n/2[2a+(n-1)d]
S12 = 12/6[2a + 11d]
S12= 6[2a + 11d] = 168
2a + 11d = 28——-(1)
Also
T3 = a + 2d = 7———(2)
Multiplying 1 by 2
2a + 4d = 14
Eqn 1 minus Eqn 3 gives
7d = 14
d = 2
Putting this in eqn 2
a + 2(2) = 7
a + (4) = 7
a = 7 – 4
a = 3
Common difference = 2
First term = 3

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(5)
TABULATE
cooking oil type|a|b|c|d|e|f|g|h
x|8|5|1|7|2|6|3|4
y|6|3|4|8|5|7|1|8
d|2|2|-3|-1|-3|-1|2|2
d²|4|4|9|1|9|1|4|4

£d² = 4+4+9+1+9+1+4+4 = 36

r = 1- 6£d²/n(n²-1)

= 1 – 6×36/8(8²-1)
= 1 – 216/504
= 1 – 0.43
= 0.57

=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=/=-=

(6a)

It follow that:
P(n) = 1/3 and p(k)¹ = 1 – 1/3 = 2/3
P(T) = 1/5 and P(T)¹ = 1- 1/5 = 4/5

Hence,
probability that only one if the them will be solve the questions will be:

= (1/3 × 4/5) + (1/5 × 2/3)
= 4/15 + 2/15
= 6/15
= 2/5

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(7)

m = 3i – 2j ; n = 2i + 3j ; p = i + 6j

Therefore:
4(3i – 2j) +2(2i +3j) -3(-i + 6j)
12i – 8j + 4i + 6j + 3i – 18j
12i + 4i + 3i – 8j + 6j – 18j
19i = 20j

=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-

(8)
m1 = 20kg
u1 = 8ms-1
m2 = 30kg
u2 = 50ms-1

(a)
In same direction
m1u1 + m2u2 = (m1+m2)v
20 × 80 + 30 × 50 = (20+30)v
1600+1500 = 50v
3100/50 = 50/50
V = 62ms-1

(b)
In opposite direction
m1u1 – m2u2 = (m1 + u2)V
20×30 – 30×50 = (20+30)V
1600 – 1500 = 50V
100/50 = 50V/50
V = 2m/s

(15)
(a)
DRAW THE DIAGRAM

(b)
(2.2) + 80(0.6) = 300(1.2) + 100 (3)
2.2B + 48 = 360 + 300
2.B + 48 = 660
2.2B = 660 – 48
2.2B = 612
Reation at B = 278.18N
Taking moment about B
80(2.1) + 300(1) = 2.2A + 100 (0.8)
224 + 300 = 2.3A + 80
524 – 80 = 2.2A
A = 444/2.2
Raction a+ A = 201.82N

 

 

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